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Jawaban:
[tex]C_{AB} = 1,5 \; \mu F[/tex]
Penjelasan:
C2 dan C3 paralel, maka
[tex]C_{23} = C_2 + C_3\\C_{23} = 2 + 4\\C_{23} = 6 \; \mu F[/tex]
C1 dan C23 (gabungan C2 dan C3) seri, maka
[tex]\frac{1}{C_{AB}} =\frac{1}{2} +\frac{1}{6} \\\frac{1}{C_{AB}} =\frac{6+2}{12}\\\frac{1}{C_{AB}} =\frac{8}{12}\\C_{AB} = \frac{12}{8} \\C_{AB} = \frac{3}{2}\\C_{AB} = 1,5 \; \mu F[/tex]
